Post by Admin on Oct 26, 2021 20:33:32 GMT 7
My name for this kind of question is: Sweet Question
Method:
Add up the number short and the number excess.
Find the difference between the number of "sweets" given at first and later.
Divide the sum by the difference and the answer is the number of "pupils".
Always check to make sure the numbers all tally.
The total number of sweets is also calculated while you are doing the check.
Example 1:
Miss Lee bought a number of sweets. At first, she wanted to give 5 sweets to each of the pupils in her class, but she found that she was short of 7 sweets. So she gave 3 sweets to each pupil and found that she had 33 sweets left. How many pupils were there in her class?
7 + 33 = 40 (Step 1: Add the number short and the number in excess)
5 - 3 = 2 (Step 2: Find the difference between the number of "sweets" given at first and later)
40 รท 2 = 20 (Step 3: Divide the sum by the difference and the answer is the number of "pupils")
Ans: 20 pupils
Check:
20 x 5 = 100
100 - 7 = 93 (short of 7)
20 x 3 = 60
60 + 33 = 93 (excess of 33)
Number of sweets is 93 in both cases, so that confirms our answer is correct.
Method:
Add up the number short and the number excess.
Find the difference between the number of "sweets" given at first and later.
Divide the sum by the difference and the answer is the number of "pupils".
Always check to make sure the numbers all tally.
The total number of sweets is also calculated while you are doing the check.
Example 1:
Miss Lee bought a number of sweets. At first, she wanted to give 5 sweets to each of the pupils in her class, but she found that she was short of 7 sweets. So she gave 3 sweets to each pupil and found that she had 33 sweets left. How many pupils were there in her class?
7 + 33 = 40 (Step 1: Add the number short and the number in excess)
5 - 3 = 2 (Step 2: Find the difference between the number of "sweets" given at first and later)
40 รท 2 = 20 (Step 3: Divide the sum by the difference and the answer is the number of "pupils")
Ans: 20 pupils
Check:
20 x 5 = 100
100 - 7 = 93 (short of 7)
20 x 3 = 60
60 + 33 = 93 (excess of 33)
Number of sweets is 93 in both cases, so that confirms our answer is correct.